A={2,3,5}
B={1,3,4}
A∩B={3}
R: a. {3}
Answer:
P (T) = 1/4
P ( T | F ) = 1/2 = P(F)
The events are not independent.
Step-by-step explanation:
Let F the event of picking the white ball first
P (F)= 1/2 ( picking the white ball first)
Let T be the event of getting the white ball twice,
P (T) = P( getting white ball) * P( getting white ball)
=( 1/2)*(1/2)
= 1/4
Here P(T∩F) = P(T) because the probability of getting the white balls is the same as probability of getting the white ball first both the times.
P ( T | F ) = P (T∩F)/ P(F)
= (1/4)/ (1/2)
= (1/2)
= 1/2 = P(F)
For the events to be independent the conditional probability P ( T | F ) must be equal to P(T).
Hence the events are not independent.
Lets plug in the numbers
2 times 2-3
4-3
1
your answer is 1
Answer:
The solutions are -3 and -1
Step-by-step explanation:
∵ y = -x² - 2x + 8
∵ y = 2x + 11
∴ -x² - 2x + 8 = 2x + 11
∴ -x² - 2x - 2x + 8 - 11 = 0
∴ -x² - 4x - 3 = 0 ⇒ divide both sides by -1
∴ x² + 4x + 3 = 0
∴ (x + 3)(x + 1) = 0
∴ x + 3 = 0 ⇒ x = -3
∴ x + 1 = 0 ⇒ x = -1
∴ The solutions are -3 and -1
