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ankoles [38]
4 years ago
13

Find the median of each set of data.

Mathematics
1 answer:
xxTIMURxx [149]4 years ago
6 0

Answer:

7 is the first one

5 is the second one

27.5 is the third one

Step-by-step explanation:

Arrange the numbers in ascending order and find the number in the middle

if there are two numbers in the middle, add them and divide by two to find the average

Hope this helps!

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The answer is (5x+3)/2 . So it’s A .
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Plz help I need help on 14, 15, 16
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3 years ago
30 book over 6 months how many in 7 months
ioda

Answer:

35

Step-by-step explanation:

5 times 6 is = 30

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5 time 7 =35

4 0
4 years ago
Read 2 more answers
What is the following sum?<br>(please show how you worked it out)
AleksAgata [21]

Answer:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Step-by-step explanation:

Let's start by breaking down each of the radicals:

\sqrt[3]{16x^3y}

Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of x^3, and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:

\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}

We can apply this same technique of "extracting cubes" to the second term:

\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}

Replacing those two expressions in the parentheses leaves us with this monster:

2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})

What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:

4, \sqrt[3]{2} , x

We can factor those out to give us a final, simplified expression:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Not that this is the same sum as we had at the beginning; we've just extracted all of the cube roots that we could in order to rewrite it in a slightly cleaner form.

6 0
3 years ago
Help plz? i don’t understand the example
nataly862011 [7]

Answer:

The example is telling you to first add up each number then divide by the amount of numbers that are present in the set. There are four in this example.

Secondly the difference between each data point will differ from each number. Basically subtract the sum from each number. Which is 5 in this case. But if its negative flip it to a positive.

Then add up each absolute value and divide by 4 twice.

7 0
3 years ago
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