The correct answer might be C not to sure
Answer:
1. B.
2. A, E.
3. D.
Step-by-step explanation:
1. 8.225 ÷ 5 = 1.645
2. 892 ÷ 8 = 111.5
8920 ÷ 80 = 111.5
894 ÷ 10 = 89.4
89.2 ÷ 0.08 = 1115
8.92 ÷ 0.8 = 11.15
0.892 ÷ 0.008 = 111.5
3. 4367 ÷ 0.004 = 1,091,750
1*60 | 60-1 =59
2*30 | 30-2 =28
3*20 | 20+3 = 23
4*15 | 15+4 =19
5*12 | 12+5 =17
6*10 | 10+6 =16
Not possible. You can get a 23. But not 22.
For (2), start with the base case. When n = 2, we have
(n + 1)! = (2 + 1)! = 3! = 6
2ⁿ = 2² = 4
6 > 4, so the case of n = 2 is true.
Now assume the inequality holds for n = k, so that
(k + 1)! > 2ᵏ
Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have
((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!
Then by our hypothesis,
(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹
and k•2ᵏ ≥ 2•2² = 8, so
k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹
which proves the claim.
Unfortunately, I can't help you with (3). Sorry!
Answer: The answer would be the second one.
Step-by-step explanation:
It is hard to explain but, I made and equation that would go with the problem which would be 2 points for every goal plus the free goals for every goal. (2g+f) and in then end it should all equal 15 so the equation so far would be 2g+f =15. This then leave you with three answers left. then I had plugged in a random number to solve it. g and f exacly should be the same number because for every goal you get a free point so if you get one goal then one extra point, if three goals then three extra points. so if you plug in 5 then 2 times 5 plus 5 is 15. The similarities between g and f is if you subtract them it is always going to be zero. Which makes the second answer correct for this problem.
