2.50+.75x
hope it helps and plz mark this brainliest!!
y=cos(x)+2
What is the amplitude of the function?
What is the period of the function?
Answer:
B) A/l
Step-by-step explanation:
Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other.
Divide l from both sides of the equation:
A = l * w
(A)/l = (l)/l * w
w = A/l
B) A/l is your answer.
~
Answer: 7x^2+21x+14
Step-by-step explanation:
(7x+7)(x+2)
Multiply each term in the first parentheses by each term in the second parentheses (FOIL)
7x×x+7x×2+7x+7×2
↘ ↙
7x×x calculate product
7x^2+7x×2+7x+7×2
↘ ↙
7x×2 calculate product
7x^2+14x+7x+7×2
↘↙
7×2 multiply numbers
7x^2+14x+7x+14
↘ ↙
21x collect like terms
7x^2+21x+14 is your end result.
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
