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jasenka [17]
3 years ago
10

The circumference of a circle is 18 m. Find its diameter, in meters. quick answers please

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

5.72957795131

Step-by-step explanation:

18/pi

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Vascular tissue

Step-by-step explanation:

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2 years ago
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A miner descended 1400 feet into a mine from the mine's entrance. While in the mine, he then rose 800 feet and then descended 45
postnew [5]
The correct answer is A.-1050
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3 years ago
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A detergent company periodically tests its products for variations in the fill weight. To do this, the company uses x-bar and R
maw [93]

Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar      R

5.8        0.42

6.1         0.38

16.02    0.08

15.95    0.15

16.12     0.42

6.18      0.23

5.87     0.36

16.2      0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

LCL=10.9361

8 0
3 years ago
Discuss the possible reasons for the differences in price in Leomande. Discuss ways to find unit prices using proportions. The l
Maru [420]
There are many reasons why there are differences in price in Lemonade.
The first is the volume or amount of the Lemonade. Obviously, the greater the amount of the Lemonade, the higher is its price.
The price of the lemonade is given, the unit price then is
$4.99/95 ounces = $0.053/ounce
Another reason is the difference in the ingredients. Some Lemonade might have additional ingredients that could make the price higher.
The difference in materials costs in different areas may also be the reason.
6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
3 years ago
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