Start by making an equation.

D is your variable.

12d=1500

Then, divide each side by 12 because there are 12 months.

12d=1500
—- ——
12. 12

d=125

Diana donates $125 per month to a charity. This is because when you have a yearly sum that is paid per month, but you don’t know the per month rate, you divide the yearly amount by 12 because there are 12 months.

I really hope this helps and you get a good grade!!

4 0

3 years ago

Read 2 more answers

Find the area of triangle of 7m 9m

BARSIC [14]

I think the answer is a=7b*9/2=31.5M

3 0

3 years ago

Please help me

Hitman42 [59]

By using algebra properties and trigonometric formulas we find that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equivalent to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ .

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

$\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ Given.

$\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}$ Subtraction between fractions with different denominator / (- 1) · a = - a.

$\frac{2\cdot \sin x}{\cos^{2}x}$ Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

$\frac{2\cdot \tan x}{\cos x}$ Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equal to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ . Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

#SPJ1

4 0

2 years ago