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3 years ago

Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Step-by-step explanation:

Given polynomials are:

$(x^3+3x^2+1)\\and\\(3x^2+6x-2)$

In order to multiply both polynomials, we will use the distributive property

So,

$= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2$

Combining like terms

$=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2$

Hence,

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Keywords: Polynomials, variables

Learn more about polynomials at:

#LearnwithBrainly

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3 years ago

Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)​

Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)