Let the second car meets the first car after n hours.
Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.
So, Distance travelled by second car = 8 + 8.5 + 9
..... 8+(n-1) 0.5.....(1)
eqn. (1) sum of n terms Of A.P with first term 8
and common difference 0.5.
Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .
Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)
From equation (2) we get, n= 9
Hence, Both the cars will meet after 9 hours.
Hope it helps!
Answer:
x^3 + 4x^2 - 7x - 10
Step-by-step explanation:
To solve this we're going to use Polynomial multiplication, starting by multiplying (x-2)(x+1) = x^2 - 2x + x - 2 = x^2 - x - 2. Next, we will multiply (x^2 - x - 2)(x+ 5) = x^3 + 5x^2 -x^2 - 5x -2x -10 = x^3 + 4x^2 - 7x - 10.
Answer:
please help help me me my question solve
C. Integers and Rational Numbers.
One centimeter equals 10 millimeters.
