We are given –
Now put the values –





- Henceforth, value of x - 9y - 3x + 6y -13 is -22.
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85x12*=1,020.
1,020-340= 680
680 total profit.
680÷85=8.
so profit for each pie is 8.00
M or the slope has to be constant throughout the graph. This is because in order for a line to be linear it has to be increasing or decreasing at the same rate. So it the slope was 2 from point x 1 -2 then the slope changed to 1 from 3-4 it would not be linear. :)
Answer:

Explanation:

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept.
Here slope: 3/2 and y-intercept: -5
Parallel slope has the same tangent slope.
Pass through point (x, y) = (6, 3)
Equation:


The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.