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alexandr1967 [171]
3 years ago
11

Between what two consecutive integers is 187

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

93 and 94

Step-by-step explanation:

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Which of the following angle pairs best describes angles 6 and 4 in the graphic below?
andriy [413]
Answer: Choice C) Same-side interior angles

------------------------------------------------------------------------------

Angle 4 and angle 6 are on the same side, in this case the right hand side of the transversal line (line t). In addition, they are on the interior of the "train tracks" horizontal  lines (line a and line b). Combine this and this is why the two angles are same-side interior angles

Side note: if line a is parallel to line b, then angle 4 and angle 6 add to 180 degrees. At this point, they are considered supplementary.
8 0
3 years ago
Can someone convert 5cm to milimeter?​
zhenek [66]

Answer: 50 millimeters

Step-by-step explanation:

5 cm is one 100th of a meter. Millimeters are one 1000th. Therefore, 1 of each unit in cm is 10 units in mm

6 0
2 years ago
Read 2 more answers
A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
center city has a population of twenty one thousand seventy people write the population in standard form
NISA [10]
The standard form is 20000 + 1000 + 70
3 0
4 years ago
Simplify the following <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Cfrac%7B1%7D%7Bx%7D%20%20%2B%201%20%7D%20%7B%20%5Cfrac%2
Anon25 [30]
Good evening, Riley!

Used properties:

\star~\boxed{\mathsf{a = \dfrac{ax}{x}, \ \ x\neq 0}}\\ \\ \\ \star~\boxed{\mathsf{\dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{ad}{bc}}}

Now, note that:

\mathsf{1 = \dfrac{x}{x},\ x\neq 0}

So:

\mathsf{\dfrac{\frac 1 x + \frac x x }{\frac 1 x} = \dfrac{\frac{x+1}{x}}{\frac 1 x}}=} \mathsf{\dfrac{x}{1}\dfrac{x+1}{x} = \boxed{x + 1}}
8 0
3 years ago
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