Answer:
51/5 m/h
Step-by-step explanation:
17 cm/min * 1/100 m/cm (convert cm to m ; 1 m = 100 cm)
17/100 m/min * 60/1 min/h (convert min to h ; 60 min = 1 h)
1020/100 m/h
simplifies to 51/5 m/h
Here we will tell you what 7990 is rounded to the nearest ten and also show you what rules we used to get to the answer.
Remember, we did not necessarily round up or down, but to the ten that is nearest to 7990.
First, 7990 rounded to the nearest ten is:
7990
Answer:
second option
Step-by-step explanation:
The left side has a solid circle at - 3 indicating x can equal - 3 denoted by ]
The arrow points left to - ∞
The right side has an open circle at - 1 indicating x cannot equal - 1 denoted by )
The arrow points right to ∞
The feasible region is the union of the 2 parts, that is
( - ∞, - 3 ] U (- 1, ∞ )
Imagine cutting this shape into two semi-circles and one rectangle.
------------------------------------------------------------------------------------------------------
- Each semi-circle has a diameter of 36 meters
- The radius would be <em>(36/2) = </em>18 meters.
--------------------------------------------------------------------
<em>We know the area of a whole circle which is π</em>
<em />
- The formula of area of a semi-circle: 1/2(π
)
<em>because a semi-circle is basically half of the whole circle!</em>
<em />
However, since we have two equal semi-circles...we can just put them together and solve for the whole circle's area.
<em>for reference: </em>
1/2(π
) + 1/2(π
) = 2/2(π
) = π
----------------------------------------------------------
First, the area of rectangle: length times width = 84 x 36 = 3024 square meters
<em>Anyways, since we have to sub in 3.14 for π </em>
Area of a whole circle: (3.14 x
) = (3.14 x
) = 1017.36 square meters
-----------------------------------------------------------
3024 + 1017.36 = 4041.36 square meters
<h2>ANSWER: J
</h2>
CBD.
The two small lines on the base are similar, and it's a right angle, so the two are similar.
Also, the position of the points has to be the same in the triangle labels.