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Brrunno [24]
4 years ago
11

Can someone help me in math please

Mathematics
1 answer:
Andrei [34K]4 years ago
8 0
<span>A∩B = </span><span>contains all of the elements that are in both sets
</span>so
answer is D. {2,4}


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(2-cos^2A)(1+2cot^2A)=(2+Cot^2A)(2-sin^2A)​
fomenos

Answer:

2 sin (2A) cos (2A)^4 + 2cos (2A)

---------------------------------------------------

                 sin (2A)

Step-by-step explanation:

7 0
3 years ago
A<br> 1200<br> b<br> 3200<br> c<br> 3680<br> d<br> 5520
anygoal [31]

Answer:

c. 3680

Step-by-step explanation:

In 2010, the population was 8000.

In 2014, it increased by 15%.

Population in 2014 :

= 8000 + 15/100×8000

= 8000 + 1200

= 9200.

Now, 2/5 of the population was age 12 or under.

= 2/5 × 9200

= 2×1840

= 3680

Answer - c) 3680

3 0
3 years ago
If x = 2 and y = 14 , evaluate the following expression: x y Give your answer as a fraction in its simplest form.
LiRa [457]

Answer:

1/7

Step-by-step explanation:

x/y

Plug in the values.

(2)/(14)

Simplify.

1/7

5 0
3 years ago
Read 2 more answers
This too!!<br><br><br><br><br> . <br> Please<br><br><br><br><br> .
REY [17]

Answer:

In order to tell if these are congruent triangles we would need to know if angles Y and V were congruent, angles X and W are congruent or if segments XU and WU were congruent.

Step-by-step explanation:

Any of these would work because you can use two different methods to telling that these are congruent triangles.

The first method is called side-angle-side. In it you need two side lengths that are congruent with a congruent angle in the middle. Since we already know that the right angle in the middle is congruent, and we know YU and VU are congruent, we would just need to know the additional side to prove congruence.

The second method is called angle, angle side. In this we need to know that two angles in a row are congruent followed by a side. Since we know the middle angle is the same, knowing either other angles would give us this method as well.

8 0
4 years ago
You invested $19,000 in two accounts paying 4% and 8% annual interest, respectively.
saveliy_v [14]

Answer:

$9000 at 4$

and

$10000 at 8%

Step-by-step explanation:

Let's assume that "x" is the amount deposited in the 4% account and "y" is the amount deposited in the 8% account.

Recall the formula for interest as : I= P * R *t

where I is the interest, R is the annual rate of interest and t is the number of years.

Since there are two investments, we need to add both interests at the end of the one year: I1 = x (0.04) (1) = 0.04 x   and   I2 = y (0.08) (1) = 0.08 y

Total Interest = Interest (from the 4% account) + Interest (from the 8% account)

Total Interest = $1160 = 0.04 x +  0.08 y

we also know that the total invested (x + y) adds to $19,000, that is:

$19,000 = x + y

Then we can solve these system of two equations by substitution, for example solving for y in the second equation and using the y substitution in the first equation;

y = 19000 - x

1160 = 0.04 x + 0.08 (19000 - x)

1160 = 0.04 x + 1520 - 0.08 x

0.08 x - 0.04 x = 1520 - 1160

0.04 x = 360

x = 360/0.04 = $9000

Then the other investment was : y = $19000 - $9000 = $10000

6 0
3 years ago
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