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skelet666 [1.2K]
3 years ago
11

The Patterson family has 3 kids, 1 boy and 2 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the

probability of a girl birth is also 1/2. What is the fractional probability of having 1 boy and 2 girls, in any order, in a family's first 3 births?
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

Probability = \frac{1}{8}

Step-by-step explanation:

Given

Represent Boys with B and Girls with G

P(B) = \frac{1}{2}

P(G) = \frac{1}{2}

Required

Find the probability or having 1 boy 2 girls

Since the order is not important, the probability is calculated as follows;

Probability = P(B) * P(G) * P(G)

Substitute \frac{1}{2} for P(B) and P(G)

Probability = \frac{1}{2} * \frac{1}{2} * \frac{1}{2}

Probability = \frac{1 * 1 * 1}{2 * 2 *2}

Probability = \frac{1}{8}

<em>Hence, the fractional probability is </em>\frac{1}{8}<em></em>

<em></em>

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