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jeka94
3 years ago
15

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Mathematics
2 answers:
kondaur [170]3 years ago
5 0

So in here we need to find the two equivalent expressions.

Let's work on 240v^2 and 8v * 30v

Well, 8v * 30v = 8 * v * 30 * v

Now let's multiply the numbers apart and the variables apart

we get: 8 * 30 * v * v = 240 * v * v = 240 * v^2 = 240v2

So the two equivalent expressions are 240v^2 and 8v*30v

Hope this helps! :)

valkas [14]3 years ago
4 0

Answer by JKismyhusbandbae: expression 2 and expression 1

Look at the four expressions. Simplify any expressions that can be simplified to see which two are equivalent.

8v × 30v = ( 8 × 30) × ( v × v) = 240v^2

Since expression 2 can be simplified to expression 1, they are equivalent.

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Solve the linear programming problem. Minimize and maximize Upper P equals negative 20 x plus 30 y Subject to 2 x plus 3 y great
Alika [10]

Answer:

Maximum = 540 at (6,14)

Minimum = 300 at (0,10) or (12,2).

Step-by-step explanation:

The given linear programming problem is

Minimize and maximize: P = 20x + 30y

Subject to constraint,

2x+3y\ge 30            .... (1)

2x+y\le 26            .... (2)

-2x+3y\le 30            .... (3)

x,y\geq 0

The related equation of given inequalities are

2x+3y=30

2x+y=26

-2x+3y=30

Table of values are:

For inequality (1).

x      y

0     10

15     0

For inequality (2).

x      y

0     26

13     0

For inequality (3).

x      y

0     10

15     0

Pot these ordered pairs on a coordinate plane and connect them draw the corresponding related line.

Check each inequality by (0,0).

2(0)+3(0)\ge 30\Rightarrow 0\ge 30    False

2(0)+(0)\le 26\Rightarrow 0\le 26     True

-2(0)+3(0)\le 30\Rightarrow 0\le 30    True

It means (0,0) is included in the shaded region of inequality (2) and (3), and (0,0) is not included in the shaded region of inequality (1).

From the below graph it is clear that the vertices of feasible region are (0,10), (6,14) and (12,2).

Calculate the values of objective function on vertices of feasible region.

Point           P = 20x + 30y

(0,10)           P = 20(0) + 30(10) = 300

(6,14)           P = 20(6) + 30(14) = 540

(12,2)           P = 20(12) + 30(2) = 300

It means objective function is maximum at (6,14) and minimum at (0,10) or (12,2).

7 0
3 years ago
There are 5,280 feet in a mile. What part of a mile, in decimal form, will you drive until you reach the exit?
Arlecino [84]
5.280 because I got it
3 0
2 years ago
Have I been solving these equations correctly?
Tresset [83]

14)


2(-3)² => 2(-3)(-3) => 2*9 = > 18


27+18-11 => 27 + 7 = > 34.


16)


\bf p(x)=\cfrac{x^2-4}{2x+1}\implies p(-8)=\cfrac{(-8)^2-4}{2(-8)+1}\implies p(-8)=\cfrac{64-4}{-16+1} \\\\\\ p(-8)=\cfrac{60}{-15}\implies p(-8)=-4


17)


\bf h(x)=3\cdot 9^x\implies h(-2)=3\cdot 9^{-2}\implies h(-2)=3\cdot \cfrac{1}{9^2} \\\\\\ h(-2)=\cfrac{3}{9^2}\implies h(-2)=\cfrac{3}{81}\implies h(-2)=\cfrac{1}{27}

4 0
3 years ago
Find the difference.<br> 3x^2y - x^2y
Murljashka [212]

Answer: 2x^2y

Step-by-step explanation:

Just subtraction.

The x is like a unit, There are 3 X's at first then subtract 1 x and you gor 2x.

Exponents will always stay the same unless there is division or multiplication involved

5 0
3 years ago
PLEASE HELP...
Sladkaya [172]

10.38

i multiplied each number and the answers that i got i added them to get the area

3 0
3 years ago
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