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lions [1.4K]
3 years ago
10

How can you determine the domain and range of a function?

Mathematics
1 answer:
lora16 [44]3 years ago
4 0

Hello!

If given a graph, you look for the point furthest to the left, and the point furthest to the right. For range you do up and down.

If you are just given a function, you can think of a few things. If you are given a radical, it must not contain a negative number. Therefore, the domain and range for that function would not contain any negative numbers; they would be greater than or equal to 0.

Also, if you have a function that involves division, you cannot divide by 0 as it is undefined. Therefore, the domain could be any real number except for 0, or a certain number that would keep any other numbers in the dividend from becoming 0.

I hope this helps!

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3 years ago
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Technetium-99m is used as a radioactive tracer for certain medical tests. It has a half-life of 1 day. Consider the function T w
Alinara [238K]

Answer:

The expression that represents the number of days until only 10% remains is T((d) 10 %) =100×(\frac{1}{2} )^{3.322}.

Step-by-step explanation:

The equation for half life is of the form

A = A₀×(\frac{1}{2} )^{\frac{t}{h} }.........................................................................(1)

Where

A = Final amount

A₀ = Initial amount

t = Time

h = Half life

For the equation T(d) = 100×2⁽⁻²⁾....................................(2)

We have by comparison with the equation for half life

2 ≡ \frac{t}{h}  and and the equation (2) can be written as

Percentage remaining after 2 half lives is

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{2 }

However if the half life of Technetium-99m is 6 hours then we have for one day

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{2 *2}

Therefore an expression that represents the number of days until only 10% remains is

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{\frac{d}{h}  } = 10 %

(\frac{1}{2} )^{\frac{d}{h}  } =\frac{1}{10}

= ㏑(\frac{1}{2} )^{\frac{d}{h}  }  = ㏑(\frac{1}{10})

= \frac{d}{h}×㏑(\frac{1}{2} ) = ㏑(\frac{1}{10})

\frac{d}{h} = \frac{ln(\frac{1}{10}) }{ln(\frac{1}{2} )} = 3.322

Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is

T((d) 10 %) =100×(\frac{1}{2} )^{3.322}

3 0
4 years ago
How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

∴ x=90

Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

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Luden [163]

The error Alex made is that he found the perimeter of the figure instead of the area.

<h3>Area and perimeter of shapes</h3>

Given the expressions

7+(3x 1.4)+5+2+(5x 14)

He used the expression to simplify the grid

The expression simplified shows that Alex added all the measures of the sides of the grid instead of taking the product of the length and width

Note that the operation Alex performed is the perimeter of the figure instead of the area hence the error Alex made is that he found the perimeter of the figure instead of the area.

Learn more on area and perimeter of figure here: brainly.com/question/443376

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Answer:

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Step-by-step explanation:

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