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Ratling [72]
3 years ago
7

What is the complete factorization of x2 − 6x + 9?

Mathematics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

(x-3)²

Step-by-step explanation:

Sati [7]3 years ago
5 0
<h2>Answer:</h2>

The factors are <u>(x-3) and (x-3)</u>

<h2>Given: </h2>

x^{2}-6 x+9

<h2>Step-by-step explanation:</h2>

In this problem, we need to find the factors which is on multiplying the factor we will get the equation.

\Rightarrow x^{2}-6 x+9

Now, we need find the sum of the coefficient of ‘x’ and product of the constant.

The coefficient of ‘x’ is written as:

\Rightarrow x^{2}-3 x-3 x+9

Now, we need to find the common multiply and divide the equation into two,

\Rightarrow x(x-3)-3(x-3)

\Rightarrow(x-3)(x-3)

\therefore(x-3)^{2}

Thus, the factor is formed which is multiplied to give the equation given in the question.

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Form a polynomial with zeros:−2 multiplicity 3; 1 multiplicity 2; 3 multiplicity 1;degree 6 You may leave your answer in factore
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Answer:

f(x) = (x+2) (x+2)^3 (x-1) (x-6)

Step-by-step explanation:

The first zero, -2, corresponds to the factor x+2 of the polynomial.

Given that this zero, -2, has multiplicity 3, (x+2)^3 represent the first three factors of the polynomial.

The next factor stems from the zero 1:  (x-1).

The next 6 factors stem from the zero 6:  (x-6).

Writing the polynomial in factored form, we get:

f(x) = (x+2) (x+2)^3 (x-1) (x-6)

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