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insens350 [35]
3 years ago
5

What is 0.5, 3/16, 0.75, 5/48 in least to greatest form?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

5/48 , 3/16 , 0.5 ,  .75

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Explain how finding 7x20 is similar to finding 7 x 2,000. Then find each product
Sphinxa [80]
7×20 and 7×2000 are similar. The amount of zeros are the dependent factor.

7×20= 140
7×2000= 14000

The base equation is 7×2=14
Any additions of zeroes in this formula will be added at the end result.

Ex.
7×2=14
7×20=140
7×200=1400
70×200=14000
700×200=140000
5 0
3 years ago
Write the expression as either the sine, cosine, or tangent of a single angle. tan5x - tan2y / 1 + tan5x tan2y
Kryger [21]
\bf \textit{Sum and Difference Identities}
\\\\
tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)}
\qquad
tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}\\\\
-------------------------------\\\\
\cfrac{tan(5x)-tan(2y)}{1+tan(5x)tan(2y)}\implies tan(5x-2y)
6 0
3 years ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6

\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
3 years ago
A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he i
Fed [463]

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

x+y=5200 or x=5200-y  .... (1)

As, total income for the two investments is $194, so equation is:

0.04x+0.03y=194   ....(2)

Putting value of x from (1) in (2)

0.04(5200-y)+0.03y=194

208-0.04y+0.03y=194

0.01y=14

y=1400

And x=5200-y

x=5200-1400=3800

Hence, money invested at 4% is $3800 and money invested at 3% is $1400

6 0
3 years ago
How would you simplify (-4r^5)(2r^8)? ​
german

Answer:

− 8 r^ 13

Step-by-step explanation:

Combine like terms

-4r and 2r= -8r

then add the exponents

5+8=13

THEN SIMPLIFY

-8r^13

8 0
4 years ago
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