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KatRina [158]
3 years ago
15

(2+(-3)(5))(3+2(-6)) using order of operations

Mathematics
1 answer:
joja [24]3 years ago
4 0

Answer:

117

Step-by-step explanation:

First, parenthesis comes first, so let's look at the first group first. After parenthesis, you should solve exponents, but there are none in this example so we'll skip that part. The next step is multiplication. If you look in (2+(-3)(5)), there is multiplication; (-3)(5). When you multiply these 2 values out, you'll get -15. But don't forget about the +2 at the beginning of the parenthesis!! When you add 2 to the the -15 we just got, you'll get -13. Moving on to the 2nd parenthesis, there is also a multiplication application of (2)(-6). When you multiply this, you get -12. But there's still the +3. If you add -12 and 3, you get -9. Now, you have to multiply your answers from both groups of parentheses together. The 2 values are -13 and -9. When you multiply these 2 together, you get 117 because the two negatives cancel each other out.

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