Question

A shipment of 17 televisions sets contains 3 defective sets. A hotel purchases 8 of these televisions sets. What is the probability that the hotel receives at least one of the defective sets?

Answer 1

Answer:

p=0.8765

Step-by-step explanation:

Let the following variables be represented as below:

Total Set,t=17

Def,d=3

Not Def,n=14

Purchases,p=8

The number of ways the hotel can receive at least one defective set in a purchase of 8 sets is calculated using the combination:-

$p(\geq 1)=1-\frac{(_dC_0)(_nC_p)}{(_tC_p)}\\p=1-\frac{(_3C_0)(_14C_8)}{(_1_7C_8)}\\p=1-0.1235\\p=0.8764$

So the proability of getting at least one defective unit is 0.8765