Question

What is the volume of a circular mine passage that is 19.0 feet in diameter and 210.0 feet long?

Answer 1

$d = diameter : d =19 \ ft \\ \\radius : r=\frac{d}{2}=\frac{19}{2}=9.5 \ ft \\\\ length of object : \ h=210 \ ft \\\\Circle Area : \ A= \pi r^2\\ \\Circular Volume = A*h = \pi r^2h \\ \\Circular Volume = \pi\cdot 9,5^2*210 =90,25 \cdot 210\cdot \pi =18952.5 \ \pi \ ft^3$