Answer:
or
Step-by-step explanation:
The given quadratic equation is

Group the constant terms on the right hand side.


Divide through by 5.

Add the square of half the coefficient of x., which is
to both sides of the equation.

The left hand side is now a perfect square.

Take the square root of both sides;



or 
or 
or 
Answer:
The width of the building is 50 lamps and 60 lamps will be needed.
Step-by-step explanation:
The perimeter is computed by the sum of the sides of the building, since the length and width are equal on the oposite sides of the building, the perimeter is given by:
perimeter = 2*length + 2*width
900 = 2*(400) + 2*width
2*width + 800 = 900
2*width = 900 - 800
2*width = 100
width = 100/2 = 50 feets
To know how many lights bulbs will be needed we need to take the perimeter of the building and divide it by the space between the lamps. We have:
number o lamps = 900/15 = 60 lamps
Answer:
The number is 30.
Step-by-step explanation:
x/5+3=9
x/5=9-3
x/5=6
x=6*5
x=30
Answer:
41.29 cm²
Step-by-step explanation:
From the question,
Area of the shaded portion = Area of the circle - area of the square.
A' = πr²-L²...… Equation 1
Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie
Given: r = 4 cm, L = 3 cm
Constant: π = 22/7.
Substitute these values into equation 1
A' = [(22/7)×4²]-3²
A' = 50.29-9
A' = 41.29 cm²
Hence the area of the shaded portion is 41.29 cm²
The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.