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sergij07 [2.7K]
3 years ago
13

I need help converting pounds into kilograms

Mathematics
2 answers:
defon3 years ago
7 0

Answer:

for an approximate result, divide the mass value by 2.205

Step-by-step explanation:

MAXImum [283]3 years ago
3 0
You need to move the decimal 2 spaces
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Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
Please answer this correctly
wolverine [178]

Answer:

1017.36 square miles

Step-by-step explanation:

Since the diameter of a circle is twice the radius, the radius of this circle is 36/2=18. Since the area of a circle is \pi r^2, the area of this circle is:

3.14 \cdot 18^2 = 1017.36

Hope this helps!

4 0
4 years ago
Read 2 more answers
1/2 base x height is area of a rectangle
shutvik [7]

Answer:

Triangle

Step-by-step explanation:

Area of a triangle

= 1/2 x base x height

7 0
3 years ago
Find the measure of the arc or angle indicated​
ycow [4]

Step-by-step explanation:

Let O be the center of the circle

We have Angle YOW = 125°

and Angle WOX = 121°.

Therefore Angle YOX = 360° - 125° - 121° = 114°.

(Sum of angles around a point is 360°)

Since Angle at Center = 2 * Angle at Circumference,

Angle YWX

= 0.5 * Angle YOX = 0.5 * 114° = 57°. (A)

6 0
3 years ago
Question 8 of 20
Gnesinka [82]
C is the answer because the X factors can’t repeat
3 0
3 years ago
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