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BARSIC [14]
3 years ago
15

A number cube is rolled and a coin is flipped. Let H stand for heads and T for tails. What is the sample space for the experimen

t?
Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer: S={(1,H) , (1,T) , (2,H) , (2,T) , (3,H) , (3,T) , (4,H) , (4,T) , (5,H) , (5,T) , (6,H) , (6,T)}


Step-by-step explanation:

Given: A number cube is rolled and a coin is flipped.

Let H stand for heads and T for tails.

Then the sample space will contain pairs in which the first one shows the number on dice and the second one shows the the outcome for coin after dice is thrown.

Now, the required sample space will be

S={(1,H) , (1,T) , (2,H) , (2,T) , (3,H) , (3,T) , (4,H) , (4,T) , (5,H) , (5,T) , (6,H) , (6,T)}

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is Justin went shopping for school clothes if the item cost $150 and he received a 10% discount what is the final price of his p
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Answer:

$135

Step-by-step explanation:

We can answer this by multiplying $150 by (1.00 - 0.10), or by 0.90:

0.90($150) = $135.

Note that 1.00($150) = $150 (full price)

and that 0.10($150) = $15 (discount)

and that (0.90)($150 = $135 (the fastest way to calculate the final (sale) price.

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Card K is reflected over the y-axis; while card N is reflected over the x-axis
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Rewrite each equation in vertex form by completing the square. Then identify the vertex.
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ANSWER

Vertex form;

y = 3( {x +  \frac{3}{2} })^{2}  -  \frac{35}{4}

Vertex

V(  - \frac{3}{2} , -  \frac{35}{4} )

EXPLANATION

Given:

f(x) = 3 {x}^{2}  + 9x - 2

We complete the square as follows:

y = 3( {x}^{2}  + 3x) - 2

y = 3( {x}^{2}  + 3x +  \frac{9}{4} ) - 2 - 3 \times  \frac{9}{4}

The vertex form is:

y = 3( {x +  \frac{3}{2} })^{2}  -  \frac{35}{4}

The vertex is

V(  - \frac{3}{2} , -  \frac{35}{4} )

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Name a point NOT contained in lines m, n, or p.
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The Highway Safety Department wants to study the driving habits of individuals. A sample of 37 cars traveling on a particular st
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Answer:

90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

Step-by-step explanation:

We are given that a sample of 37 cars traveling on a particular stretch of highway revealed an average speed of 70.7 miles per hour with a standard deviation of 6.3 miles per hour.

Firstly, the pivotal quantity for 90% confidence interval for the true mean is given by;

                            P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average speed of cars = 70.7 miles per hour

             s = sample standard deviation = 6.3 miles per hour

             n = sample of cars = 37

             \mu = true mean speed

<em>Here for constructing 90% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 90% confidence interval for the true mean, \mu is ;

P(-1.688 < t_3_6 < 1.688) = 0.90  {As the critical value of t at 36 degree of

                                 freedom are -1.688 & 1.688 with P = 5%}  

P(-1.688 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.688) = 0.90

P( -1.688 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.688 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.688 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.688 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<em><u>90% confidence interval for</u></em> \mu = [ \bar X-1.688 \times {\frac{s}{\sqrt{n} } } , \bar X+1.688 \times {\frac{s}{\sqrt{n} } } ]

                    = [ 70.7-1.688 \times {\frac{6.3}{\sqrt{37} } } , 70.7+1.688 \times {\frac{6.3}{\sqrt{37} } } ]

                    = [68.9517 miles per hour , 72.4483 miles per hour]

Therefore, 90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

<em>The interpretation of the above interval is that we are 90% confident that the true mean speed of all cars will lie between 68.9517 miles per hour and 72.4483 miles per hour.</em>

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