The vase of the triangle would be x because it is unknown and the height would be x+2 because it is 2 more units than the base the formula for the area of a triangle is (base)(height)% 2 =area so (x)(x+2)%2=12 so then you have 1/2x^2+x=12 at this point I would move the 12 to the other side by subtracting to get 1/2x^2+x-12=0 then I would multiply it all by 2 to get x^2 + 2x-24 from there I would factor to get (x+6)(x-4) and your answers would be x= -6 and 4 and because 6 is negative it would not work because distances are always positive so the base would equal 4
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Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer:
y=4/3x - 5
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
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