Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
The mean is the average of the numbers. You add up all numbers and divide the result for how many numbers there are (14)
6+2+59+12+11+9+9+54+54+46+2+32+43+11 = 350
Mean = 350/14 = 25
A) 180-125 =55
B) both bottom angles are 55 and the triangle's angles should add up to 180, so 55 + 55 + x = 180. X = 70
C) CAE and CBD are equal so the bottom angle (that was calculated in A) will be the base acute angle —>55
Answer:
2×16
=32
Step-by-step explanation:
hope it helps..