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11Alexandr11 [23.1K]
3 years ago
6

Please help me out and explain it to me​

Mathematics
2 answers:
grigory [225]3 years ago
8 0

I do not understand because I solved it and got x=-3+square 6 i

Step-by-step explanation:

there is various places u can find how to solve it. Ill send you a link.

Please mark the brainliest!!!!

vodka [1.7K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

x^2-6x+25=0

A quadratic equation can be solved by using the quadratic formula, x = (-b (+/-) \sqrt{b^{2}-4ac }) /2a

So the equation to start with is ax^2+bx+c=0, thus your equation has the same layout.

a= 1

b= -6

c= 25

Then plug it in

x=( -(-6) (+/-) \sqrt{6^{2}-4(1)(25) } )/2(1)\\x= (6(+/-) \sqrt{36-100} )/2\\x= (6(+/-)\sqrt{-64} )/2

When you have a negative in the root you have to take out an i

i = -i^{2}

So when you take it out the negative isn't there anymore so you can simplify normally

Now split up the plus and minus

x= (6 + 8i)/2\\x= 3+4i\\x= (6-8i)/2\\x= 3-4i\\x= (3-4i) and (3+4i)

So the answer is A

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kirza4 [7]
Whattttttt help meeeee
5 0
3 years ago
What is the shape of the graph of the function?<br> h(t) = 0.32 - 0.5t
allsm [11]

Answer:

Answer (a) is correct

Step-by-step explanation:

This is not the same function that was given to you in the problem.

As you have typed it, this function is linear.  The one in the homework problem is exponential.

We will ignore the linear function h(t) = 0.32 - 0.5t.

We will focus on h(t) = 0.32 - 0.5^t.

If t = 0, then 0.5^t = 0.5 ^0 = 1, and so h(0) = 0.32 - 1 = -0.68  =>  (0, -0.68)

Continuing with a few other t values chosen at random:

h(1) = -0.18

h(2) = 0.07

Notice that h is increasing as x increases!

h(4) = 0.2575

and so on.

answer A is the correct one.

h(1) = 0.32 - 0.5^1 = 0.32 - 0.5 = -0.18

4 0
3 years ago
Please help me!!!!!!
aev [14]
- 10, you go down 4 - this is shown because to get from two to 10 in two, you have to go 2+4=6+4=10
8 0
2 years ago
Read 2 more answers
PLEASE help me out!!!!!!!!!
ExtremeBDS [4]

Answer: Screams internally

Step-by-step explanation:

6 0
3 years ago
What is the most precise classification of the quadrilateral formed by connecting the midpoints of the sides of a square?
e-lub [12.9K]
A square again
Lets take a is side of a square.
if u take parts of square from mid point and measure distance or length of any sides that would be a/2

then use Pythagorean theorem to solve hypotenuse u will get all length of small quadrilateral a/√2.same for all sides.
I see that will be square again
7 0
3 years ago
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