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gtnhenbr [62]
3 years ago
5

What is the solution to the equation?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

A.) - 1/5

Step-by-step explanation:

I divided each side by factors that do not contain the variable.

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Factor the expression 3w - 6
Musya8 [376]
3 is common and therefore the factorization of the expression will be

3(w-2)
8 0
3 years ago
PLEASE HELP!!<br> What was the average number of locations chosen per potential customer?
MatroZZZ [7]

Answer: D.2

Step-by-step explanation:

First,

Add all the number together.

32+24+16+8

=80

Next,

80 divided by amount of customers.

80 / 40 = 2


Therefore the average is 2.

3 0
2 years ago
Answer correctly with good explanation. Please and thank you
Kaylis [27]

Answer:

The cost is $352.80

Step-by-step explanation:

step 1. 14 * 12 = 168 ----> find out the area (base times height)

step 2. 168 * 2.10 = 352.80 -----> multiply the area with the cost of per square foot of the carpet

I hope this helped :))

8 0
2 years ago
Trees are subjected to different levels of carbon dioxide atmosphere with 6% of them in a minimal growth condition at 350 parts
podryga [215]

Answer:

Mean = 528 ppm

Standard deviation = 90.8 ppm

Step-by-step explanation:

Assuming a basis of 100 trees

6 trees with 350 ppm (minimal growth)

10 trees with 450 ppm (slow growth)

47 trees with 550 ppm (moderate growth)

37 trees with 650 ppm (rapid growth)

Mean = xbar = Σx/N

x = each variable

xbar = mean

N = number of variables = 100

Σx = sum of all variables = sum of all the ppm = (6×350) + (10×450) + (47×550) + (37×550) = 52800

xbar = 52800/100 = 528 ppm

Standard deviation = σ = √[Σ(x - xbar)²/N]

x = each variable

xbar = mean = 528

N = number of variables = 12

Σ(x - xbar)² = [6(350 - 528)²] + [10(450 - 528)²] + [47(550 - 528)²] + [37(650 - 528)²] = 824400

σ = √[Σ(x - xbar)²/N] = √(824400/100) = 90.8 ppm

5 0
3 years ago
Determine whether the point is on the graph of the equation 2x+7y=13
Fofino [41]

Answer:

(I) yessssssssssssssssssssssss

6 0
3 years ago
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