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konstantin123 [22]
3 years ago
13

¡Ayuda!

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer:

La magnitud del desplazamiento resultante es 2045.463 kilómetros. La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

Step-by-step explanation:

En primer lugar, se construye el triángulo. La figura resultante se encuentra incluida como archivo adjunto. La magnitud del desplazamiento resultante se determina mediante la Ley del Coseno:

r = \sqrt{(800\,km)^{2}+(1400\,km)^{2}-2\cdot (800\,km)\cdot (1400\,km)\cdot \cos 135^{\circ}}

r \approx 2045.463\,km

La magnitud del desplazamiento resultante es 2045.463 kilómetros.

La dirección del desplazamiento resultante es hallada por medio de la Ley del Seno, sabiendo que el ángulo del desplazamiento resultante a la recta de 1400 kilómetros:

\frac{1400\,km}{\sin \alpha} = \frac{2045.463\,km}{\sin 135^{\circ}}

Se despeja el ángulo correspondiente:

\alpha = \sin^{-1}\left(\frac{1400\,km}{2045.463\,km}\times \sin 135^{\circ} \right)

\alpha \approx 28.945^{\circ}

La dirección absoluta del desplazamiento resultante es:

\alpha' = 180^{\circ}-\alpha

\alpha' = 180^{\circ}-28.945^{\circ}

\alpha' = 151.055^{\circ}

La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

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