Answer:
b) y = 3x + 1
y = x+1
Step-by-step explanation:
Select all the systems of equations that have exactly one solution.
a)
y = 3x + 1
y = 3x + 7
y - 3x = 1.... Equation 1
y - 3x = 7...... Equation 2
We solve using Elimination
We Subtract Equation 2 from 1
(y - y ) - (3x - 3x) = 7 - 1
0 = 6
b) y = 3x + 1...... Equation 1
y = x +1...... Equation 2
x = y - 1
We substitute y - 1 for x in Equation 1
y= 3(y - 1) + 1
y = 3y - 3 + 1
y - 3y = -3 + 1
-2y = -2
y = -2/-2
y = 1
Solving for x
x = y - 1
x = 1 - 1
x = 0
x = 0, y = 1,
The Equations in b) have only one solution
c) x+y=10
x = 10 - y
2x+2y=20
We substitute
2(10 - y) + 2y = 20
20 - 2y + 2y= 20
-2y + 2y = 20 - 20
0 = 0
It has no solution
d) x+y=10.... Equation 1
x+y=12..... Equation 2
We solve using Elimination
We Subtract Equation 2 from 1
x - x + y - y = 12 - 10
0 = 2
Answer:
The "non-included" side in AAS can be either of the two sides that are not directly between the two angles being used. Once triangles are proven congruent, the corresponding leftover "parts" that were not used in SSS, SAS, ASA, AAS and HL, are also congruent.
(write in own words)
Answer:
12c8/d2.....option 1.........