The formula in order to obtain the vertex form of a
quadratic equation is given as
y=a(x-h)^2+k where (h,k) is the vertex of the quadratic
equation which is parabolic in shape and it is opening upward.
As given in the problem, y=6x^2+12x-10
Using the formula, we can transformed the quadratic equation
y=6x^2+12x-10 into its vertex form:
y=6x^2+12x-10
<span>y= (6x^2+12x)-10 (grouping)</span>
y=6(x^2+2x)-10 (factoring Common terms per
group)
y=6(x^2+2x+1)-10-6 (Completing the squares)
<span>y=6(x+1)^2-16
(Factor and Simplify) </span>
Hence, the vertex form of y=<span>6x^2+12x-10 is y=6(x+1)^2-16</span>
