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Kruka [31]
3 years ago
10

Which situation represents 25 x + 500 ≥ 50 x + 250?

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

move 50x on to the other side then move 500 to the other side too so that it reads 25x-50x *sign*250-500

Step-by-step explanation:

-25x*sign*-250 divide both sides by 25so answer x*sign*100

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Circle A contains all positive odd numbers; circle B contains all factors of 33, and circle C contains all prime numbers. How ma
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3 and 11 are the only two because 33 only has four factors: 1,3,11,33.
1 - in some cases people say this is prime, but it is now widely considered to not be a prime number
3 - prime
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3 years ago
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A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu
Romashka-Z-Leto [24]

Answer:

P( At least one of the two cards was a heart)=7/16

Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= \frac{3}{4}×\frac{3}{4}

=\frac{9}{16}

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- \frac{9}{16}

=\frac{7}{16}

Second way:

Probability that first card drawn is a heart and the second one is not a heart= \frac{1}{4}×\frac{3}{4}

=\frac{3}{16}

Probability that the first card drawn is not a heart and the second one is a heart= \frac{3}{4}×\frac{1}{4}

=\frac{3}{16}

Probability that both cards drawn are hearts= \frac{1}{4}×\frac{1}{4}

=\frac{1}{16}

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= \frac{7}{16}


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