Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
A..................................................
Answer:
Length
inches
Width
inches
Step-by-step explanation:
Let
= length of rectangle,
= width of rectangle
Given the area and the perimeter of the rectangle, we can write:
![2l+2w=80](https://tex.z-dn.net/?f=2l%2B2w%3D80)
So:
![l+w = 80\div2](https://tex.z-dn.net/?f=l%2Bw%20%3D%2080%5Cdiv2)
![=40](https://tex.z-dn.net/?f=%3D40)
![l=40-w](https://tex.z-dn.net/?f=l%3D40-w)
Now, we can use substitution to find the value of
:
![lw = 375](https://tex.z-dn.net/?f=lw%20%3D%20375)
![(40-w)w = 375](https://tex.z-dn.net/?f=%2840-w%29w%20%3D%20375)
![40w-w^2 = 375](https://tex.z-dn.net/?f=40w-w%5E2%20%3D%20375)
(Quadratic equation)
∴ ![w = 15, 25](https://tex.z-dn.net/?f=w%20%3D%2015%2C%2025)
We can use substitution again to find the value of ![l](https://tex.z-dn.net/?f=l)
![lw = 375](https://tex.z-dn.net/?f=lw%20%3D%20375)
![l=375\div w](https://tex.z-dn.net/?f=l%3D375%5Cdiv%20w)
![=25,15](https://tex.z-dn.net/?f=%3D25%2C15)
∵ Length usually refers to the longer side of a rectangle, ∴ length
inches and width
inches.
Hope this helps :)
Answer:
y = 6x - 47
or
6x - y - 47 = 0
Step-by-step explanation:
![y - y_{1} = m(x - x_{1} ) \\ \\ plug \: x_{1} = 7 \\ y_{1} = - 5 \\ m = 6 \: in \: the \: above \: equation \\ y - ( - 5) = 6(x - 7) \\ \\ y + 5 = 6x - 42 \\ \\ y = 6x - 42 - 5 \\ \\ y = 6x - 47 \\ \\ or \: 6x - y - 47 = 0](https://tex.z-dn.net/?f=y%20-%20%20y_%7B1%7D%20%3D%20m%28x%20-%20%20x_%7B1%7D%20%29%20%5C%5C%20%20%5C%5C%20plug%20%5C%3A%20x_%7B1%7D%20%3D%207%20%5C%5C%20%20y_%7B1%7D%20%3D%20%20-%205%20%5C%5C%20m%20%3D%206%20%5C%3A%20in%20%5C%3A%20the%20%5C%3A%20above%20%5C%3A%20equation%20%5C%5C%20y%20-%20%28%20-%205%29%20%3D%206%28x%20-%207%29%20%5C%5C%20%20%5C%5C%20y%20%2B%205%20%3D%206x%20-%2042%20%5C%5C%20%20%5C%5C%20y%20%3D%206x%20-%2042%20-%205%20%5C%5C%20%20%5C%5C%20y%20%3D%206x%20-%2047%20%5C%5C%20%20%5C%5C%20or%20%5C%3A%206x%20-%20y%20-%2047%20%3D%200)
Answer:
QR ≈ 16.3
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
57 QR = 926.9 ( divide both sides by 57 )
QR ≈ 16.3 ( to the nearest tenth )