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boyakko [2]
3 years ago
5

Identify the value that is NOT in range of the piecewise function. A. -3 B. -2 C. 3

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

Option A i.e. y = - 3 is not in range of the piece wise function graphed.

Step-by-step explanation:

The range of a function y = f(x) is given by the possible values of y for the possible domain (x-values) of the function.

Now, it is clear from the graph of the function that the value of y never goes below y = - 2.

The graph is drawn in such a way that any value of y less than - 2 and greater than - ∞ is not in the range of the function.

Therefore, option A i.e. y = - 3 is not in range of the piecewise function graphed. (Answer)

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Some one please help me with this geometry problem ASAP
Elden [556K]

Answer:

43.5

Step-by-step explanation:

Set it up like 3x-5+x+1=180. Combine the variables and the numbers without a letter next to it. 4x+6=180. Subtract 6 from 180. Divide that number by 4.

6 0
3 years ago
Whats 1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+8+9+9
k0ka [10]

Answer:

90 is your answer

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
What is a way to write 11 more than twice x is less than 44
madam [21]

(2x) + 11 < 44

x is multiplied by two because we are looking for twice of x. 11 is added to the 2x because we are looking for eleven more than the sum of twice of x. Since 2x + 11 is less than 44, we use the lesser than ( < ) symbol.

4 0
3 years ago
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Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
What is the equation of the line that passes through (4, 3) and (2, 2)?
anastassius [24]
(4,3)(2,2)
slope = (2 - 3) / (2 - 4) = -1/-2 = 1/2

y = mx + b
slope(m) = 1/2
use either of ur sets of points...(4,3)...x = 4 and y = 3
now we sub and find b, the y int
3 = 1/2(4) + b
3 = 2 + b
3 - 2 = b
1 = b

so ur equation is : y = 1/2x + 1 <==
4 0
4 years ago
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