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Aleonysh [2.5K]
3 years ago
5

0.70 writing decimals as fraction ?

Mathematics
2 answers:
forsale [732]3 years ago
8 0
0.70 can be concerted to a fraction by multiplying by 100. SO the answer is 70%
photoshop1234 [79]3 years ago
8 0
Answer: 0.70 is the same as 70/100. Please make this the brainliest answer.
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Suzie's Slushes has increasing profits each week during the hot summer months. Suzie finds that
Assoli18 [71]

Answer:

Approximately to the nearest cent :

$1856

Step-by-step explanation:

We are told in the above question that:

Suzie's profit increases every month by 30%

We are told that in the first month her profit is $300

Step 1

We are to find the profit for the other weeks:

First week Profit = $300

b) Second week =

$300 × 30/100 = $90

Total amount for the second week= $90 + $300

= $390

c) Third week

$390 × 30/100 = $117

Total amount for the third week = $117 + $390

= $507

d) Fourth week

$507 × 30/100 = $152.1

Total amount for the fourth week = $152.1 + $507

= $659.1

Total Amount of money she would make after 4 weeks =

Profit of the first week + Total Amount for the first week + Total Amount for the second week + Total Amount for the third week + Total Amount for the fourth week

= $300 + $390 + $507 + $659.1

= $1856.10

Approximately to the nearest cent the amount of money will she make in all over 4 weeks is :

$1856

3 0
3 years ago
A father is 7 times as old as his son. The sum of their ages is 56 years. What is the age of each?
Doss [256]

Answer:

The son is 7, the father is 49.

Step-by-step explanation:

This was a guess-and-check process. I knew this answer was correct because  7*7=49, and 49+7=56.

4 0
3 years ago
Read 2 more answers
What is the answer will mark as branliest
zzz [600]

Answer:

∠MON = 57°

Step-by-step explanation:

∠LOM +  ∠MON = ∠LON ← substitute values

3x + 20 + 2x + 33 = 113, that is

5x + 53 = 113 ( subtract 53 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

Hence

∠MON  = 2x + 33 = (2 × 12) + 33 = 24 + 33 = 57°

4 0
3 years ago
Can u show the step and thanks
Rudiy27

Answer:

B) 378 students could be expected to attend the game.

Step-by-step explanation:

Out of 40 students, 45% agreed,

45% of 40

= 45/100 * 40

= 18 students,

18 students out of 40 agreed.

So, Out of 840 students 18/40 * 840 students would be expected to agree. We get :- 378

4 0
3 years ago
Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a
kompoz [17]

<u>Answer:</u>

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

<u>Solution:</u>

Given, Elena bikes 20 minutes each day for exercise.  

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,  

We know that, distance travelled = speed \times time

a. At a constant speed of 13 miles per hour for the entire 20 minutes  

Her speed is 13 miles per hour.  

Then, distance D miles = 13 miles per hour \times 20 minutes

\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes  

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

D = M mph \times 5 minutes + N mph \times 15 minutes

\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }

\mathrm{D}=\mathrm{M} \times \frac{1}{12}+\mathrm{N} \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{N}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{3 N}{12} \rightarrow 12 \mathrm{D}=\mathrm{M}+3 \mathrm{N} \text { miles }

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

8 0
4 years ago
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