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Monica [59]
3 years ago
15

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 84.5 cm and diameter 2.40 cm fr

om a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g = 9.80 m/s2 .
Physics
1 answer:
omeli [17]3 years ago
8 0

Answer:

29.22 N

Explanation:

Parameters given:

Density = 7800 kg/m³

Diameter of rod = 2.4cm = 0.024m

Radius = 0.012m

Length = 84.5cm = 0.845m

To find the weight, we must find get the mass.

Density is given as:

Density = mass/volume

Therefore, mass is:

Mass = density * volume

Volume of the cylindrical rod is:

Volume = pi * r² * h

Volume = 3.142 * 0.012² * 0.845

Volume = 0.0003823 m³

Mass = 7800 * 0.0003823

Mass = 2.982 kg

Weight = m * g

Where g is acceleration due to gravity

Weight = 2.982 * 9.8 = 29.22 N

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Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
The PE of the box that is on a 2.0 m high self is 1600 J. What is the power expelled to lift the box to this height in 10.0 seco
Pani-rosa [81]

Answer:

  160 W

Explanation:

Power is the ratio of work to time:

  (1600 J)/(10 s) = 160 J/s = 160 W

7 0
3 years ago
PLEASE ANSWER FAST I WILL GIVE BRAINLIEST
TiliK225 [7]

Explanation:

The answer is:

A squirrel runs up the trunk of a tree.

3 0
3 years ago
Read 2 more answers
This problem has been solved!
lana66690 [7]

Answer:

Charge on each metal sphere will be 8\times 10^{8}C

Explanation:

We have given number of electron added to metal sphere A n=10^{12}electron

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres =\frac{10^{12}}{2}=5\times 10^{11}electron

We know that charge on each electron e=1.6\times 10^{-19}C

So charge on both the spheres will be equal to q=1.6\times 10^{-19}\times 5\times 10^{11}=8\times 10^{8}C

So charge on each metal sphere will be equal to 8\times 10^{8}C

6 0
3 years ago
two idential train engines are parked on parallel track. one engine has ten cars attached and the other has no cars attached. ea
nikklg [1K]

Answer:

The second engine with no cars will accelerate more.

Explanation:

Since the engines are identical so they hacve the same mass. The first engine has 10 cars attached which adds more mass to it whereas second engine has no cars attached.

Therefore second engine is lighter in mass than the first one.

<u>We know from the Newton's second law of motion:</u>

F=m.a

\therefore a=\frac{F}{m}

Now, according to question both the engines exert same force for moving.

We see that :

a\propto\frac{1}{m}

So more is the mass, lesser is the acceleration, hence the second engine with no cars will accelerate more.

6 0
3 years ago
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