The answer is f because it equals 1/3 and f is 1/3
T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15
Multiply the above equation by 1.03 giving
1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16
Now subtract the first equation from the second to give
0.03T = 40000(1.03)^16 - 40000
0.03T = 40000(1.03^16 - 1)
0.03T = 24188.26
T = 24188.26 / 0.03 = $806275.25
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
I think any number mor than 3
Answer:
y=6x+11
Step-by-step explanation:
