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Ivan
3 years ago
9

Select the equations that are parallel and perpendicular to y = 2x - 1 and that pass through the point (4, 1).

Mathematics
2 answers:
Flura [38]3 years ago
7 0

parallel: y = 2x - 7 perpendicular: y = -1/2x + 3

german3 years ago
7 0
Parallel lines are lines that do not meet no matter how much you extends the lines. Equations of these lines are characterized by having the same slopes. Perpendicular lines are lines that intersect at a point and forms a right angle or an angle of 90 degrees. Therefore, the correct answer from the choices is option 1.

parallel: y = 2x - 7
<span>perpendicular: y = -1/2x + 3</span>
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Read 2 more answers
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nordsb [41]

Answer:

<h3>perpendicular line:    y = -¹/₆ x + 4¹/₃ </h3><h3>  parallel line:              y = 6x - 45 </h3>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = 6x - 7   ⇒   m₁=6

6×m₂ = -1        ⇒    m₂ = -¹/₆

 

The line y=-¹/₆ x+b passes through point (8, 3) so the equation:

3 = -¹/₆ ×8 + b must be true

3 = -⁴/₃ + b

b = 4¹/₃

Therefore equation in  slope-intercept form:

                                                     y = -¹/₆ x + 4¹/₃

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 6x - 7   ⇒   m₁=6   ⇒   m₂=6

The line y=6x+b passes through point (8, 3) so the equation:

3 = 6×8 + b must be true

3 = 48 + b

b = -45

Therefore equation in  slope-intercept form:

                                                     y = 6x - 45

7 0
3 years ago
7.
Iteru [2.4K]

Answer:

a. 45 π

b. 12 π

c. 16 π

Step-by-step explanation:

a.

If a 3×5 rectangle is revolved about one of its sides of length 5 to create a solid of revolution, we can see a cilinder with:

Radius: 3

Height: 5

Then the volume of the cylinder is:

V=π*r^{2} *h= π*(3)^{2} *(5) = π*(9)*(5)=45 π

b. If a 3-4-5 right triangle is revolved about a leg of length 4 to create a solid of revolution. We can see a cone with:

Radius: 3

Height: 4

Then the volume of the cone is:

V=(1/3)*π*r^{2} *h= (1/3)*π*(3)^{2} *(4) = (1/3)*π*(9)*(4)=12 π

c. We can answer this item using the past (b. item) and solving for the other leg revolution (3):

Then we will have:

Radius: 4

Height: 3

Then the volume of the cone is:

V=(1/3)*π*r^{2} *h= (1/3)*π*(4)^{2} *(3) = (1/3)*π*(16)*(3)=16 π

7 0
3 years ago
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