Answer:
m<MON = 100°
Explanation:
Given:
Area of shaded sector LOM = 2π cm²
NL = 6 cm
Required:
m<MON
Solution:
m<MON = 180° - m<LOM (angles in a straight line)
We don't know m<LOM. Therefore, let's find m<LOM.
Area of a sector = θ/360 × πr²
Area of sector LOM = 2π cm²
r = 3 cm
θ = m<LOM = ?
Plug in the values
2π = m<LOM/360 × π × 3²
2π = m<LOM/360 × 9π
2π = m<LOM × 9π/360
2π = m<LOM × π/40
Multiply both sides by 40
2π × 40 = m<LOM × π
80π = m<LOM × π
Divide both sides by π
80π/π = m<LOM
80 = m<LOM
m<LOM = 80°
✔️m<MON = 180° - m<LOM (angles in a straight line)
Substitute
m<MON = 180° - 80°
m<MON = 100°
Greece but sorry if thats not what you mean.
The correct answer is: inserted names, dates, and places often make a statement accurate.
We are given,
60-day 10%, $4,500 note accepted by Hong Company from Indigo Company.
The journal entry needed to record the transaction by Indigo Company is cash payment or disbursement journal. This contains all transactions with payments and disbursements. This includes overdue accounts and accounts payable. <span />
