What is 31/30 devided by 15

Vika [28.1K]

1.25

If you take the difference between two y axis numbers (say 5 and 10) which is 5 and the difference between two X axis numbers (say 4 and 8) which is 4. The y axis is the rise(5) and the x axis is the run(4). Using the formula rise/run (5/4) you can calculate the answer to be 1.25.

5 0

2 years ago

Question 1 2 pts Logic Puzzle: A certain clock runs fast; it indicates that 1 hour has passed when actually only 56 minutes have

Liono4ka [1.6K]

Using proportions, it is found that the correct time when it reads 10:30pm is of 9:40 pm.

<h3>What is a proportion?</h3>

A proportion is a fraction of total amount, and the measures are related using a rule of three.

In this problem, when 56 minutes have passed, the clock indicates that 60 minutes have passed. Hence, what is the time passed when the clock indicates that 12 hours and 30 minutes, that is, 60 x 12 + 30 = 750 minutes have passed?

Hence, the <em>rule of three</em> is:

56 minutes - 60 minutes

x minutes - 750 minutes

Applying cross multiplication:

$60x = 56 \times 750$

$x = \frac{56 \times 750}{60}$

$x = 700$

700 minutes is 660/60 = 11 hours + 40 minutes after 10:00 am, hence the correct time is of 9:40 pm.

You can learn more about proportions at brainly.com/question/24372153

7 0

2 years ago

1. Find the vertex of the following: y = (x - 4)(x - 10) *

horsena [70]

Answer:

1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

$\frac{-b}{2a}$

First make the equation into a quadratic equation.

$(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40$

Now it is in the form

$ax^{2} +bx+c=0$

Now we can substitute the values

$\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7$

Now we have 7 as our x value for the vertex we can substitute for y,

$x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9$

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

$x-4=0\\x=4\\\\x-10=0\\x=10$