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Lady bird [3.3K]
4 years ago
13

Graph the point-slope equation: y+6=2(x+3)

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
4 0
Your slope is 2 and your Y-intercept is 0.
To graph, plot the dot at 0 and the slope is by 2
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Help!<br> Change 2/5<br> to a percent.
nalin [4]

Answer:

40%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If the principal is $300 rate 3% time 4 years then what is the interest earned and the new balance
Tomtit [17]

Answer:

a) Interest earned = $36

New Balance  = $336

b) Interest rate  = 0.05 or 5%

New Balance = $517.5

c) time t = 5

New Balance = $612.5

d) Principal Amount = $675

New Balance =  $783

Step-by-step explanation:

We are given:

a) Principal (P) = $300

Rate (r) = 3% or 0.03

Time (t)= 4 years

Interest earned = ?

The formula used is: Simple \ Interest (I)= P\times r\times t

Putting values and finding interest

Simple \ Interest (I)= P\times r\times t\\Simple \ Interest (I)= 300\times 0.03\times 4\\Simple \ Interest (I)= 36

So, Interest earned = $36

New Balance = Principal + Interest = 300+36 = $336

b) a) Principal (P) = $300

Rate (r) = ?

Time (t)= 3 years

Interest earned = 67.50

The formula used is: Simple \ Interest (I)= P\times r\times t

Putting values and finding rate

Simple \ Interest (I)= P\times r\times t\\67.50= 450\times r\times 3\\67.50=1350\times r\\r=\frac{67.50}{1350}\\r=0.05 \ or \ 5\%

So, Interest rate  = 0.05 or 5%

New Balance = Principal + Interest = 450+67.50 = $517.5

c) Principal (P) = $500

Rate (r) = 4.5% or 0.045

Time (t)= ?

Interest earned = $112.50

The formula used is: Simple \ Interest (I)= P\times r\times t

Putting values and finding time

Simple \ Interest (I)= P\times r\times t\\112.50= 500\times 0.045\times t\\112.50=22.5 \times t\\t=\frac{112.50}{22.5}\\t=5

So, time t = 5

New Balance = Principal + Interest = 500+112.50 = $612.5

d) Principal (P) = ?

Rate (r) = 8% or 0.08

Time (t)= 2 years

Interest earned = 108.00

The formula used is: Simple \ Interest (I)= P\times r\times t

Putting values and finding Principal

Simple \ Interest (I)= P\times r\times t\\108=P\times 0.08 \times 2\\108=P\times 0.16\\P=\frac{108}{0.16}\\P=675

So, Principal Amount = $675

New Balance = Principal + Interest = 675+108 = $783

8 0
3 years ago
There are 81 cal in a 3/4 cup serving of chicken noodle soup how many calories are in a 2/3 cup serving?
tangare [24]

Answer:

There are 72 cal in 2/3 cup serving of noodle soup

Step-by-step explanation:

The given parameters are;

The amount of calories in 3/4 cup serving of chicken noodle soup = 81 cal

The amount of calories in a 2/3 cup serving is given as follows;

3/4 cup contains 81 cal

1 cup contains 81/(3/4) cal = 81 × 4/3 cal = 108 cal

1 cup contains 108 cal

2/3 cup contains = 2/3 × 1 cup = 2/3 × 108 cal = 72 cal

2/3 cup contains 72 cal

Therefore, there are 72 cal in 2/3 cup serving of noodle soup.

5 0
3 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
HELP PLEASE
Georgia [21]

Answer:

\huge\boxed{\sf No}

Step-by-step explanation:

Evan spent 20 hours doing homework last week

25 hours were spent this week.

<u>Let's see what 125% of 20 equals:</u>

= (125 / 100) * 20

= (125 / 10) * 2

= 125 / 5

= 25 hours

But,

<u>It is written that Evan thought he spent 125 % more than the last week which means:</u>

= (125% of 20) + 20

= 25 + 20

= 45 hours

He should've said that he has given 25% more time than the last week.

(<u>Note that:</u> 25 % of 20 equals 5 so 25 % more than last week will be equal to (25 % + 20) = (5+20) = 25)

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
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