When the balloon is on the ground, it is at point 0. It starts to go up at 5 f/m for a time of 4 minutes. So we will multiply 5 by 4 to get 20. At this point, the balloon is 20 feet off the ground. However, we now know that the balloon descends at 2 f/m at a time of 7 minutes. So we must multiply 2 by 7 to get 14. So we know it was at 20, and then it went down by 14.
20 - 14 = 6 feet
This means that the balloon is now 6 feet above the ground.
I hope I've helped! :)
A giant star is a star with substantially larger radius and luminosity than a main-sequence (or dwarf) star of the same surface temperature. They lie above the main sequence (luminosity class V in the Yerkes spectral classification) on the Hertzsprung–Russell diagram and correspond to luminosity classes II and III.
Answer:
3 to the 4th power.
Step-by-step explanation:
Basically, here 3 to the 3rd power is 27. Multiplying it by 3 is only adding another power, making it 81, which is the same answer to 3 to the 4th power if that makes sense.
Step-by-step explanation:
Let alpha be the unknown angle. We can set up our sine law as follows:
or
Solving for alpha,
Addition expression: -6 + 14 = 8
-6 because it’s below street level.
