answer:
$0.02
<em>-- let me know if you have any questions regarding this. </em>
C, because you need to change them to the same fractions, 4/8 and 5/8.
Double them and you get 8/16 and 10/16, in the middle being 9/16.
52s + 30b because 52 x s + 30 x b = 52s + 30b
Answer: the average distance between the parabola is 2000
Step-by-step explanation:
Given that;
y = 30x(20 - x) and the x-axis on the interval [0, 20]
f(x) = y = 30x(20 - x); [0, 20] and a=0, b=20
the average distance between the parabola will be
Average value = 1/20-0 ²⁰∫₀ 30x(20-x) dx
= 1/20 ²⁰∫₀ (600x-30x²) dx
= 1/20 [(600x)/2 - (30x³)/3]₀²⁰
= 1/20 [300x - 10x³]₀²⁰
inputting the limits, we get
= 1/20 [(300 × 20 × 20 - 10 × 20 × 20 × 20) - 0 - 0]
= 1/20 ( 120000 - 80000)
= 0.05 × 40000
<h2>= 2000</h2>
Therefore the average distance between the parabola is 2000
<h3 />
it's 12.56
Step-by-step explanation:
=2×22/7×2
=2×22×2/7
=88/7
1=2.56
