If poaching reduces the population of an endangered animal by 6% and the criteria of population extinction is 20 with present population 1500 then it will take 3.62 years to reach to the mark of extinction.
Given Poaching reduces the population of endangered animals by 6% per year. The criteria of population extinction is 20. Present population being 1500.
Number of years taken by the population of endangered animals to reach to 20 mark can be calculated as under:
20=1500*
20=1500*
20/1500=
0.133=
take log both sides
log(0.133)=log-------1
log(0.133)=nlog (0.94)
put the values log values:
log(0.133)=-0.8761
log(0.94)=-0.0268
Taking 1
-0.8761=n*(-0.0268)
n=0.8761/0.0268
n=3.269
Hence to reach level of 20 the population takes 3.2 years.
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The solution to the system of equation are x=2, y=0, z=6
<h3>System of equations</h3>
System of equations are equations that contains unknown variables.
Given the equations
3x+y+2z=8
8y+6z=36
12y+2z=12
From equation 2 and 3
8y+6z=36 * 1
12y+2z=12 * 3
______________
8y+6z=36
36y+6z= 36
Subtract
8y - 36y = 36 - 36
-28y =0
y = 0
Substitute y = 0 into equation 2
8(0)+6z=36
6z = 36
z = 6
From equation 1
3x+y+2z =8
3x + 0 + 2(6) = 8
3x = 8 - 12
3x = 6
x = 2
Hence the solution to the system of equation are x=2, y=0, z=6
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Answer:
p+2=-15 step1:-2 on both sides
p=-17
p=-17