What is the justification for step 2 in the solution process?
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Answer:
The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
That is z with a pvalue of , so Z = 2.575.
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 696.58 - 7.28 = 689.3 pieces
The upper end of the interval is the sample mean added to M. So it is 696.58 + 7.28 = 703.86 pieces
The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.