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Pavel [41]
3 years ago
10

Estimate square root of21

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0
Square root of 21 is 

<span>4.58257569496
</span>
I rounded it to 4.58

frozen [14]3 years ago
4 0
Well, 21 isn't a perfect square, but we can estimate it and write it in decimal, which is:
<span>4.58257569496 or 4.6</span>



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A lumber company is making doors that are 2058.02058.0 millimeters tall. If the doors are too long they must be trimmed, and if
nataly862011 [7]

Answer:

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

df=n-1=15-1=14  

p_v =P(t_{(14)}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

Step-by-step explanation:

Data given and notation    

\bar X=2044 represent the sample mean    

s=17 represent the sample standard deviation    

n=15 sample size    

\mu_o =2058 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is lower than 2058 mm, the system of hypothesis are :    

Null hypothesis:\mu \geq 2058    

Alternative hypothesis:\mu < 2058    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=15-1=14  

Since is a one-sided lower test the p value would be:    

p_v =P(t_{(14)}    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

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I dont know who is up but if you are open a another tab on your laptop and look up loser .com
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Answer:

I did and I must say I don't know what I was expecting but he deserved it.

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The answer will be 45 because it’s a right angle
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Answer:

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Step-by-step explanation:

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Answer:

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