Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
Answer:
I will take $36,230.5 to pay for the education of child.
Explanation:
Cash Invested in the saving account will earn a return of 8% each year and this amount could be withdrawn by the me to pay for the education of child.
We will use following formula to calculate the annual payments
P = r ( PV ) / [ 1 - ( 1+ r )^-n ]
where
PV = amount of investment = $120,000
r = rate of return = 8%
n = number of period = 4 years
P = 8% ( 120,000 ) / [ 1 - ( 1 + 0.08 )^-4 ]
P = 36,230.5
Answer:
Franchising
Explanation:
just took the test and got 100%
Answer:
c.Equilibrium price will rise; equilibrium quantity will rise.
Explanation:
If there's an increase in demand and supply remains unchanged. The demand curve would shift to the right and there would be an excess of demand over supply. Equilibrium price and quantity would increase.
I hope my answer helps you
Answer:
I think I think it will be 2:35 or 2:50
