Answer:
$7.50
Step-by-step explanation:
I had the same question and I put this answer and got it correct.
Answer:
200,000 m
Step-by-step explanation:
We will multiply the length of the ant by the number of ants to find out how long the line is.
10 million is 10 with 6 zeros
20 * 10 ^-3 move the decimal 3 places to the left
20. * 10 ^-3 = .02
.02 * 10000000
200000
The sum (+) of 14 and a number (x) is equal to (=) 7.
14 + x = 7
To solve, subtract 14 from both sides.
x = -7
Answer:
the answer is 131.4
Step-by-step explanation:
32.85/3= 10.95
10.95×12= 131.4
Answer:
The mean of the remaining 3 boys is 51.
Step-by-step explanation:
The mean mark of the entire group (
), dimensionless, is:
(Eq. 1)
(
)
(Eq. 1b)
Where 
is the mark of the i-th boy, dimensionless.
In addition, we know the following mean marks from statement:
(Eq. 2)
(
)
(Eq. 2b)
(Eq. 3)
Where:
- Mean mark of the first 7 boys, dimensionless.
- Mean mark of the remaining 3 boys, dimensionless.
By applying sum properties in (Eq. 1b) and using (Eq. 2b) and (Eq. 3), we obtain the mean of the remaining 3 boys:
![\frac{1}{10}\cdot [\Sigma_{i = 1}^{7}x_{i}+\Sigma_{i=8}^{10}x_{i}] = 58](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%5Ccdot%20%5B%5CSigma_%7Bi%20%3D%201%7D%5E%7B7%7Dx_%7Bi%7D%2B%5CSigma_%7Bi%3D8%7D%5E%7B10%7Dx_%7Bi%7D%5D%20%3D%2058)
![\frac{1}{10}\cdot [7\cdot (61)+3\cdot p_{3}] = 58](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%5Ccdot%20%5B7%5Ccdot%20%2861%29%2B3%5Ccdot%20p_%7B3%7D%5D%20%3D%2058)
The mean of the remaining 3 boys is 51.
