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Rama09 [41]
2 years ago
12

(-8)+(-12)+(-5)+(-9)

Mathematics
1 answer:
Sav [38]2 years ago
3 0

Answer:

(-8)+(-12)+(-5)+(-9)

=-8-12-5-9

=-(8+12+5+9)

=-34

Step-by-step explanation:

-×-=+

+×+=+

-×+=-

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Solve and simplify, typing the final answer as a fraction 1/4 ÷ 3/8
natita [175]

[ Answer ]

2 / 3


[ Explanation ]


1 * 8 / 4 * 3


8 / 12


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2 / 3


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6 0
2 years ago
Read 2 more answers
Plz help me with number 1. Plz!!!!
snow_tiger [21]

Answer:

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Step-by-step explanation:

3 0
2 years ago
If you double radius of a circle, how does this affect the area of the circle
arlik [135]
It would quadruple the area of the circle.
5 0
3 years ago
The area of a circular oil slick on the surface of the sea is increasing at a rate of [150m^2/s] how fast is the radius changing
Akimi4 [234]

Answer with Step-by-step explanation:

We are given that

\frac{dA}{dt}=150m^2/s

a.Radius =25 m

We have to find rate of change of radius.

We know that

Area of circle,A=\pi r^2

Differentiate w.r.t time

\frac{dA}{dt}=2\pi r\frac{dr}{dt}

Substitute the values then we get

150=2\pi (25)\frac{dr}{dt}

\frac{dr}{dt}=\frac{150}{50\pi}=\frac{3}{\pi} m/s

\frac{dr}{dt}=\frac{3}{\pi} m/s

b.A=1000m^2

Substitute the values then we get

1000=\pi r^2

\pi=3.14

r^2=\frac{1000}{3.14}

r=\sqrt{\frac{1000}{3.14}}=17.8m

\frac{dA}{dr}=2\pi r\frac{dr}{dt}

Substitute the values then we get

150=2\pi(17.8)\frac{dr}{dt}

\frac{dr}{dt}=\frac{150}{2\pi(17.8)}=\frac{150}{35.6\pi}m/s

\frac{dr}{dt}=\frac{75}{17.8\pi}m/s

4 0
2 years ago
What volume of ice cream is contained in a 10 cm-high ice cream cone with a base radius of 4 cm?
Ivahew [28]
Volume of a cone= \pi r   ^{2}  \frac{h}{3}
When you calculate it, you will get 167.55
Then you will round that to 168.
So, the answer is D. 168 cubic cm


8 0
3 years ago
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