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lilavasa [31]
3 years ago
9

There are going to be presentations at a school. If 30 people can fit in a room, how many rooms are necessary if there area tota

l of 40 people going to the presentations?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
7 0
Hello again lol. I would think it would be two rooms don’t count me on this one but I think it is two
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For the problem, use the discriminant to determine the number of real solutions for the equation. Then, find the solutions and c
Ksivusya [100]

Answer:

Discriminant = 55.2 > 0 -> 2 real solutions

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

Step-by-step explanation:

To find the time when the ball will reach the height of 2 meters, we just need to use the value of h = 2 in the equation given. So, we have that:

−4.9t^2 − 4t + 4 = 2

−4.9t^2 − 4t + 2 = 0

For this equation, we have the constants a = -4.9, b = -4 and c = 2. So the discriminant Delta is:

Delta = b^2 - 4ac = 16 + 39.2 = 55.2

sqrt(Delta) = 7.4297

As Delta > 0, we have 2 real solutions

t1 = (-b + sqrt(Delta)) / 2a = (4 + 7.4297) / (-9.8)  = -1.1663 s

t2 = (-b - sqrt(Delta)) / 2a = (4 - 7.4297) / (-9.8)  = 0.35 s

Number of real solutions: 2

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

8 0
2 years ago
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telo118 [61]

Answer:

54° and 110°

Step-by-step explanation:

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Then

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35x - 30 = 180 ( add 30 to both sides )

35x = 210 ( divide both sides by 35 )

x = 6

Then

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The inscribed angle YVW is half the measure of its intercepted arc YW, so

arc YW = 2 × 87° = 174°, then

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9.296 times 10 to the 7th power in standard form
Volgvan
The answer is 9,2960000
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