All categories

3 years ago

YMBCA donates 90,000 dollars. MECH donates twice that amount. How much money was donated?

Mathematics

2 answers:

Sergio [31]3 years ago

7 0

Answer: $270,000

Step-by-step explanation:

YMBCA = $90,000

MECH = ($90,000)(2) = $180,000

Total = YMBCA + MECH = $90,000 + $180,000 = $270,000

natima [27]3 years ago

4 0

Answer:

$270,000 was donated.

Twice refers to 2 times the amount, so 90,000 x 2 gives you 180,000. Now YMBCA also has 90,000 dollars. Add 90,000 to 180,000 and the total is 270,000.

You might be interested in

To gather information on customer satisfaction, a researcher goes into each store and interviews six randomly selected customers

Slav-nsk [51]

Answer:

Convenience sampling.

Step-by-step explanation:

To gather information on customer satisfaction, a researcher goes into each store and interviews six randomly selected customers at each store. This sampling technique is called convenience sampling.

Convenience sampling can be defined as a sampling method which involves the researcher selecting or collecting data that is easily available or choosing the individuals who are easiest to reach in a population. It is a type of non-probability method of sampling where the first or easiest available data source is being used by the researcher without other requirements.

In this scenario, to gather information on customer satisfaction, the researcher went to the store most likely situated in a shopping mall to collect data from six (6) customers in each stores.

Some of the advantages of convenience sampling are low cost, data are collected quickly, lesser rules etc.

3 0

3 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

3 0

3 years ago

Read 2 more answers

Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)

Blizzard [7]

Answer:

One possible equation is $f(x) = (x + 3)\, (x - 5)$ , which is equivalent to $f(x) = x^{2} - 2\, x - 15$ .

Step-by-step explanation:

The factor theorem states that if $x = x_{0}$ (where $x_{0}$ is a constant) is a root of a function, $(x - x_{0})$ would be a factor of that function.

The question states that $(-3,\, 0)$ and $(5,\, 0)$ are $x$ -intercepts of this function. In other words, $x = -3$ and $x = 5$ would both set the value of this quadratic function to $0$ . Thus, $x = -3\!$ and $x = 5\!$ would be two roots of this function.

By the factor theorem, $(x - (-3))$ and $(x - 5)$ would be two factors of this function.

Because the function in this question is quadratic, $(x - (-3))$ and $(x - 5)$ would be the only two factors of this function. In other words, for some constant $a$ ( $a \ne 0$ ):

$f(x) = a\, (x - (-3))\, (x - 5)$ .

Simplify to obtain:

$f(x) = a\, (x + 3)\, (x - 5)$ .

Expand this expression to obtain:

$f(x) = a\, (x^{2} - 2\, x - 15)$ .

(Quadratic functions are polynomials of degree two. If this function has any factor other than $(x - (-3))$ and $(x - 5)$ , expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of $a$ corresponds to a distinct quadratic function with $x$ -intercepts $(-3,\, 0)$ and $(5,\, 0)$ . For example, with $a = 1$ :