All categories

4 years ago

Name two physical properties that characterize matter

Physics

1 answer:

STatiana [176]4 years ago

8 0

Answer:

Matter have two essential types of properties, those are physical properties and chemical properties.

Explanation:

You might be interested in

A sample of gold has a volume of 2 cm3 and a mass of 38.6 grams. What would be the density, and three other properties of the sa

lukranit [14]

The density of the gold is calculated to be "19,300 kg/m³".

<u>Explanation:</u>

Given:

Volume = 2cm³

Mass = 38.6 grams.

To Find:

Density of the gold = ?

Solution:

Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.

Mass in grams is converted into kg as,

1 g = 0.001 kg

38. 6 g = $\frac{38.6}{1000} = 0.0386 kg$

Now we have to convert cm³ to m³ as,

1 cm³ = 10⁻⁶ m³

2 cm³ = 2 × 10⁻⁶ m³

So Density = $\frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}$

Physical properties of Gold:

Gold is a heavy metal.

It is Malleable and ductile.

It is a corrosion resistant element.

3 0

3 years ago

A 2-kg ball is moving with a speed of 4 m/s, and a 4-kg ball is moving with a speed of 2 m/s. What can you conclude about the of

Mila [183]

<h2>Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>

Explanation:

Kinetic energy = 0.5 x Mass x Velocity²

For ball of mass 2 kg

Mass, m = 2 kg

Velocity, v = 4 m/s

Kinetic energy = 0.5 x 2 x 4² = 16 J

For ball of mass 4 kg

Mass, m = 4 kg

Velocity, v = 2 m/s

Kinetic energy = 0.5 x 4 x 2² = 8 J

Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball

4 0

4 years ago

Nine-year-old Dakoda realizes that the quantity of water in a glass remains the same, even when the water is poured into a diffe

Archy [21]

Answer:

Conservation

Explanation:

She has observation conservation because If the temperature of the liquids stays constant and the container is insulated and not heat or cool the liquid much would not change the density of the liquid very much so that it's original volume could remain constant.

The interesting thing is not that the child assumes the taller glass holds more liquid but that they fail to understand conservation: the fact that the water from one glass is going to be the same amount after being poured into any other container. It's as if they did not realize the water came from the same glass.

3 0

3 years ago

The current through inductance L is given by I=I0e−t/τ

ohaa [14]

ΔVl = L di/dt
i = i₀e -t/T
di/dt = i₀ × (-1/T) e -t/T
ΔVl = L× (-I/T i₀e -t/T
ΔVl = -L/T i₀e -t/T

b. 15mm, i₀ = 36mA, T = 1.1m
t= Os
ΔVl = 0,491V
C. t = 1ms
ΔVl = 0.198V
t = 2ms
ΔVl = 0.08V

E. t = ms
ΔVl = 0.032V

6 0

4 years ago

At time t=0 a 2150 kg rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. This forc

amm1812

Explanation:

Given that,

Mass of the rocket, m = 2150 kg

At time t=0 a rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. The force is given by equation :

$F=At^2$

Here F = 888.93 N when t = 1.25 s

$F=At^2\\\\A=\dfrac{F}{t^2}\\\\A=\dfrac{888.93}{(1.25)^2}\\\\A=568.91\ N/s^2$

The value of A is $568.91\ N/s^2$ .

(a) Let J is the impulse does the engine exert on the rocket during the 4.0 s interval starting 2.00 s after the engine is fired. It is given in terms of force as :

$J=\int\limits {F{\cdot} dt}$

Limits will be from 2 s to 2+ 4 = 6 s

It implies :

$J=\int\limits^6_2 {At^2{\cdot} dt}\\\\J=A\int\limits^6_2 {t^2{\cdot} dt}\\\\J=A\dfrac{t^3}{3}|_2^6\\\\J=568.91\times \dfrac{1}{3}\times (6^3-2^3)\\\\J=39444.42\ Ns$

(b) Impulse is also equal to the change in momentum as :

$J=m\Delta v\\\\\Delta v=\dfrac{J}{m}\\\\\Delta v=\dfrac{39444.42}{2150}\\\\\Delta v=18.34\ m/s$

Hence, this is the required solution.

5 0

3 years ago