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3 years ago

What are the solutions to the quadratic equation?2x^2+7x+6=0

Mathematics

1 answer:

adell [148]3 years ago

7 0

Answer:

x=-3/2,-2

using the quadratic formula 2x² is your a 7x b and 6 your c you want to substitute those numbers into the equation and then solve to find the solutions

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10.<br> JKLM is a rhombus KLN is a triangle. Find MKN.

rjkz [21]

Answer:

65°

Step-by-step explanation:

JM = JK (all sides of a rhombus are equal)

Angle JKM = 25° (isosceles triangle)

Angle JKL = 50° (consecutive angles of rhombus)

Angle MKL = 25° (angle subtraction)

Angle MLK = 130° (opposite angles of a rhombus)

Angle KLN = 50° (angles on a straight line)

Angle LKN = 40° (angle sum of triangle)

Angle MKN = 65° (angle addition)

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1 year ago

Need help and it's for monday<br><br> is Science

IrinaVladis [17]

Answer:

a. Yes, it will float in oil since it is less dense than oil.

b. No, it won't float in oil since it is more dense than the oil itself.

c. Yes, it will float in water since, the water is more dense than the object itself.

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2 years ago

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5v + 7f =28.70 if f is 2.85

adell [148]

Hey!

First, let's write the problem.
$5v+7\left(2.85\right)=28.7$
Multiply $7$ with $2.85$ .
$5v+19.95=28.7$
Subtract $19.95$ from both sides.
$5v+19.95-19.95=28.7-19.95$
$5v=8.75$
Divide both sides by $5$ .
$\frac{5v}{5}=\frac{8.75}{5}$
$v=1.75$

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

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3 years ago

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PLEASE ANSWER

Natasha2012 [34]

Answer:

Step-by-step explanation:

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2 years ago

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Vavilen inflated a huge balloon in 19 minutes. Then he poked a hole in the balloon so that it slowly leaked air out until it was

kaheart [24]

Considering balloon to be an spherical object

Volume of sphere = $\frac{4}{3}\pi r^3$ , where r is the radius of sphere.

After 19 minutes ,If radius of balloon changes from r to R, the Volume changes from V to V'.

V'= $\frac{4}{3}\pi R^3$ ,

As given,rate at which the air leaked out of the balloon (in liters of air per minute) was half of the rate at which Vavilen inflated the balloon.

Also, $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

Now, again the radius changes from R to r.So, Volume changes from V' to Back to V.

Time taken by the balloon to deflate = 38 minutes

But there is no relation between time and volume of Balloon.

So, we can't predict at which rate balloon is deflating or inflating.Apart from the statement given in Question: $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

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3 years ago

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What are the solutions to the quadratic equation?2x^2+7x+6=0​

What are the solutions to the quadratic equation?2x^2+7x+6=0