The answer is c.
(a)
x * 2 = y
2 * 2 = 4
3 * 2 = 6
4 * 2 = 8 not 9
(b)
unknown formula
(c)
x * 3 = y
4 * 3 = 12
5 * 3 = 15
6 * 3 = 18
(d)
x * 4
1 * 4 = 4
2 * 4 = 8
3 * 3 = 9 not 15
Answer:
55 = 5 × 11
Step-by-step explanation:
The only prime factors of 55 are 5 and 11, thus
55 = 5 × 11
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to

Answer:
7/24
Step-by-step explanation: